如何使用PHP的simplexml_load_string获取XML标记（包含名称空间）的值？

Question

How do I get the value of "TagOne" (i.e. foo) and TagTwo (i.e. bar) from the XML below using simplexml_load_string? I'm stumped by the namespace called "ns" in the tag.

<?xml version="1.0" encoding="UTF-8"?>

<SOAP-ENV:Body>

    <ns:ExampleInterface_Output xmlns:ns="http://example.com/interfaces">
        <ns:TagOne>Foo</ns:TagOne>
        <ns:TagTwo>Bar</ns:TagTwo>
    </ns:ExampleInterface_Output>

</SOAP-ENV:Body>

Thanks very much for your kind help!

Answer 1

Check this code:

<?php

$xml = <<<XML
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:xsd="http://www.w3.org/2001/XMLSchema"
                   xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
                   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <SOAP-ENV:Body>
        <ns:ExampleInterface_Output xmlns:ns="http://example.com/interfaces">
            <ns:TagOne>Foo</ns:TagOne>
            <ns:TagTwo>Bar</ns:TagTwo>
        </ns:ExampleInterface_Output>
    </SOAP-ENV:Body>
</SOAP-ENV:Envelope>
XML;

$xse = new SimpleXMLElement($xml);
$exampleInterface = $xse
    ->children('SOAP-ENV', true)
    ->children('ns', true);

foreach ($exampleInterface->children('ns', true) as $key => $value) {
    //Do your stuff
}