doudengshen5591 2013-05-02 14:49
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如何使用php创建一个搜索栏输入来搜索表的每一列

I am creating a search bar which will search the query from every column of my database table and will prompt the output I am doing this with php and mysqli but now I dont have any idea to how do I show my output. can anybody help me here is my code

if(!$db) {
    require("includes/db.php")
    echo 'ERROR: Could not connect to the database.';
} else {
    if(isset($_POST['queryString'])) {
        $queryString = $db->real_escape_string($_POST['queryString']);
        if(strlen($queryString) >0) {
            $query = $db->query("SELECT * FROM mdb  WHERE name LIKE '%" . $queryString . "%' OR grno LIKE '%". $queryString ."%'
                                    OR `address` LIKE '%". $queryString ."%', `city` LIKE '%". $queryString ."%' OR pin LIKE '%". $queryString ."%'
                                    OR mobile LIKE '%". $queryString ."%' OR `email` LIKE'%". $queryString ."%'  ORDER BY vouchno LIMIT 8");


            if($query) {
                $catid = 0;
                while ($result = $query ->fetch_object()) {
                    //no idea how do I show the result here
                }
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  • doulian5857 2013-05-02 15:45
    关注

    just to answer your question heres the code

    if(!$db) {
    require("includes/db.php")
    echo 'ERROR: Could not connect to the database.';
    } else {
    if(isset($_POST['queryString'])) {
        $queryString = $db->real_escape_string($_POST['queryString']);
        if(strlen($queryString) >0) {
            $query = $db->query("SELECT * FROM mdb  WHERE name LIKE '%" . $queryString . "%' OR grno LIKE '%". $queryString ."%'
                                    OR `address` LIKE '%". $queryString ."%', `city` LIKE '%". $queryString ."%' OR pin LIKE '%". $queryString ."%'
                                    OR mobile LIKE '%". $queryString ."%' OR `email` LIKE'%". $queryString ."%'  ORDER BY vouchno LIMIT 8");
    
    
            if($query) {
                $catid = 0;
                $results = array();
                while ($result = $query ->fetch_object()) {
                    //no idea how do I show the result here
                    $results[] = $result;
                }
    
                /* use the $results to show the result using foreach or forloop*/
    

    But please consider the comments above.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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