duanjing1023 2014-01-14 00:51
浏览 29
已采纳

使用ajax发布变量将不起作用

I have some data, processed with javascript that I want to write to a database. So I'm trying to code something with ajax. But with no luck...

What I need: I have two variables (id, naam) that I want to pass to a php-script. Nothing more...

<script type='text/javascript'>

function geefNaam(id, naam)
{
  $.ajax({
  type: "POST",
  url: "schrijfrecord.php",
  data: { id: id, naam: naam },
  })
}
</script>

and I call this function...

geefNaam(id, naam);

my php

<?php

$id = $_POST['id'];
$naam = $_POST['naam'];

echo $id;
echo $naam;
?>
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1条回答 默认 最新

  • dongwuli5105 2014-01-14 01:01
    关注

    First remove , after data: { id: id, naam: naam },. Also you aren't doing anything after your $.ajax call. Use success: function(){} or .done(). I would use $.post():

    //<![CDATA[
    <script type='text/javascript'>
    function geefNaam(id, naam, where){
        $.post('schrijfrecord.php', {id: id, naam: naam},
          function(result){
            where.html(result);
          }
        });
    }
    $('#someElement').click(function(){
      geefNaam('someId', 'someName', $('#wherever'));
    });
    //]]>
    </script>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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