2017-08-09 12:58
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I used below code to display another website on my site

  $turl = $_GET['turl'];
  $ch = curl_init($turl);
  curl_setopt( $ch, CURLOPT_POST, false );
  curl_setopt( $ch, CURLOPT_FOLLOWLOCATION, true );
  curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.0; 
  en-US; rv:1.7.12) Gecko/20050915 Firefox/1.0.7");
  curl_setopt( $ch, CURLOPT_HEADER, false );
  curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
  $data = curl_exec( $ch );

 echo $data;

but when I tried to display facebook or youtube the result looks like-

enter image description here

图片转代码服务由CSDN问答提供 功能建议


  $ turl = $ _GET ['turl']; 
 $ ch = curl_init($ turl); 
 curl_setopt($ ch,CURLOPT_POST,false); 
 curl_setopt($ ch,CURLOPT_FOLLOWLOCATION,true); 
 curl_setopt  ($ ch,CURLOPT_USERAGENT,“Mozilla / 5.0(Windows; U; Windows NT 5.0; 
 en-US; rv:1.7.12)Gecko / 20050915 Firefox / 1.0.7”); 
 curl_setopt($ ch,CURLOPT_HEADER  ,false); 
 curl_setopt($ ch,CURLOPT_RETURNTRANSFER,true); 
 $ data = curl_exec($ ch); 
 echo $ data; 
 <  p>但是当我试图显示facebook或youtube时,结果看起来像 -   

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1条回答 默认 最新

  • dspym82000 2017-08-09 13:02

    Because curl only gets html (source code) of specified url and i think styles are addressed relatively on server(not full path). this is why no style has been found . you can also check console in google chrome or firefox by pressing F12 on each browsers and see errors.

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