douxian8883 2014-11-27 21:05
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在Golang中将结构指针转换为接口指针

I have a function

func doStuff(inout *interface{}) {
   ...
}

the purpose of this function is to be able to treat a pointer of any type as input. But when I want to call it with a the pointer of a struct I have an error.

type MyStruct struct {
    f1 int
}

When calling doStuff

ms := MyStruct{1}
doStuff(&ms)

I have

test.go:38: cannot use &ms (type *MyStruct) as type **interface {} in argument to doStuff

How can I cast &ms to be compatible with *interface{}?

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  • douchen3562 2014-11-27 21:11
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    There is no such thing as a "pointer to an interface" (technically, you can use one, but generally you don't need it).

    As seen in "what is the meaning of interface{} in golang?", interface is a container with two words of data:

    • one word is used to point to a method table for the value’s underlying type,
    • and the other word is used to point to the actual data being held by that value.

    interface

    So remove the pointer, and doStuff will work just fine: the interface data will be &ms, your pointer:

    func doStuff(inout interface{}) {
       ...
    }
    

    See this example:

    ms := MyStruct{1}
    doStuff(&ms)
    fmt.Printf("Hello, playground: %v
    ", ms)
    

    Output:

    Hello, playground: {1}
    

    As newacct mentions in the comments:

    Passing the pointer to the interface directly works because if MyStruct conforms to a protocol, then *MyStruct also conforms to the protocol (since a type's method set is included in its pointer type's method set).

    In this case, the interface is the empty interface, so it accepts all types anyway, but still.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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