duan00529
2015-03-15 14:30
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golang:将uint32(或任何内置类型)转换为[] byte(写入文件)

I'm trying to convert an uint32 to a byte array (4 bytes) in Go using the unsafe library:

h := (uint32)(((fh.year*100+fh.month)*100+fh.day)*100 + fh.h)
a := make([]byte, unsafe.Sizeof(h))
copy(a, *(*[]byte)(unsafe.Pointer(&h)))

The first two lines are correct, but then I get a runtime error ( unexpected fault address ) at the copy call.

The next step would be to call Write

_, err = fi.Write(a)

to write the 4 bytes into a file.

I've found other questions with a similar topic, but none with a working code. I'm also aware that unsafe is unsafe.

Any help would be greatly appreciated.

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1条回答 默认 最新

  • duandu2980 2015-03-15 15:07
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    Here's one way to do it:

    h := (uint32)(((fh.year*100+fh.month)*100+fh.day)*100 + fh.h)
    a := (*[4]byte)(unsafe.Pointer(&h))[:]
    

    Here's a breakdown of what's going on. The code

    (*[4]byte)(unsafe.Pointer(&h))
    

    converts the uint32 pointer to a [4]byte pointer. The

    [:]
    

    at the end creates a slice on the [4]byte.

    The code in the question interprets the uint32 as a slice header. The resulting slice is not valid and copy faults.

    An alternative approach that does not use unsafe is to use the encoding/binary package:

    h := (uint32)(((fh.year*100+fh.month)*100+fh.day)*100 + fh.h)
    a := make([]byte, 4)
    binary.LittleEndian.PutUint32(a, h)
    
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