从stdin读取以空格分隔的整数到int slice中

Question

I'm trying to read from stdin two lines of an unknown number of space-separated integers. I would like to store each lines ints into their own int slice.

For example, my input may look like this:

1 2 3
4 5 6

and I want to read this into two []int:

[1,2,3]
[4,5,6]

This is what I have so far. scanner.Scan() is giving me the line, but I'm not sure how to convert that into a []int:

package main
import (
    "fmt"
    "os"
    "bufio"
)

func main() {
    var firstLine []int
    var secondLine []int

    scanner := bufio.NewScanner(os.Stdin)
    for scanner.Scan() {
        t := scanner.Text()
    }
}

Answer 1

For example,

numbers.go:

package main

import (
    "bufio"
    "fmt"
    "os"
    "strconv"
    "strings"
)

func numbers(s string) []int {
    var n []int
    for _, f := range strings.Fields(s) {
        i, err := strconv.Atoi(f)
        if err == nil {
            n = append(n, i)
        }
    }
    return n
}

func main() {
    var firstLine, secondLine []int
    scanner := bufio.NewScanner(os.Stdin)
    for i := 1; i <= 2 && scanner.Scan(); i++ {
        switch i {
        case 1:
            firstLine = numbers(scanner.Text())
        case 2:
            secondLine = numbers(scanner.Text())
        }
    }
    fmt.Println(firstLine)
    fmt.Println(secondLine)
}

Output:

$ go run numbers.go
1 2 3
4 5 6
[1 2 3]
[4 5 6]
$