douren1928
douren1928
2016-06-29 22:09

如何使用Golang http.ResponseWriter将HTML字符串显示为网页?

已采纳

I'm following along the example in Chapter 19 from The Way to Go.

This is the content of my main.go

package main

import (
    "fmt"
    "net/http"
)

const AddForm = `
<form method="POST" action="/add">
URL: <input type="text" name="url">
<input type="submit" value="Add">
</form>
`

func main() {
    http.HandleFunc("/add", Add)
    http.ListenAndServe(":8080", nil)
}

func Add(w http.ResponseWriter, r *http.Request) {
    url := r.FormValue("url")
    if url == "" {
        fmt.Fprint(w, AddForm)
        return
    }
    key := "Placeholder"
    fmt.Fprintf(w, "http://localhost:8080/%s", key)
}

According to the book and its screenshot, I should see a valid form rendered in my browser. But right now, I can only see the raw string.

I'm very new to go, so I'm not sure if the language has evolved a lot since the example was written. My go version is go version go1.6.2 linux/amd64 and I think the book is written in 2012 with older version of go.

How do I modify it to make it render as a form in the browser? Thanks.

  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 复制链接分享
  • 邀请回答

2条回答

  • doulin4844 doulin4844 5年前

    After reading through the doc, in current version of golang, http.ResponseWriter has a default Content-type as text/plain, and after manually set the content type as text/html, things are working as expected.

    if url == "" {
        w.Header().Set("Content-Type", "text/html; charset=utf-8")
        fmt.Fprint(w, AddForm)
        return
    }
    
    点赞 评论 复制链接分享
  • duanpo7282 duanpo7282 5年前

    If you use HTML templates it is better. Template checks your HTML for errors too.

    https://play.golang.org/p/l9bUoWC4PZ

    In Execute if you used w instaed of stdout in my example the content type would automatically be set

    点赞 评论 复制链接分享

相关推荐