dtsnx44260 2014-02-11 08:30
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I want to parse the following string to a date in go:

"This item will be released on March 9, 2014."

I followed this and came up whith:

func findReleaseDateString(raw string) time.Time {
  test, err := time.Parse("This item will be released on January 2, 2006.", raw)
  if err != nil {

 return test

Which works like a charm for english strings.

My problem: I would like to parse german strings. Like:

"Dieser Artikel wird am 9. März 2014 erscheinen."

I am aware, that I could match day, month and year via a regex and then parse it. But is there any possibility to tell time.Parse to use a different set of constants for month?

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  • douhanshu5517 2014-02-11 08:56

    There is currently no i18n support for the time package. While waiting for that to happen, you can try using a wrapper package such as:


    As stated by monday's documentation:

    Monday is not an alternative to standard time package. It is a temporary solution to use while the internationalization features are not ready.

    That's why monday doesn't create any additional parsing algorithms, layout identifiers. It is just a wrapper for time.Format and time.ParseInLocation and uses all the same layout IDs, constants, etc.

    Here is your example using monday:

    package main
    import (
    func findReleaseDateString(raw string) time.Time {
        loc, _ := time.LoadLocation("Europe/Berlin")
        t, err := monday.ParseInLocation("Dieser Artikel wird am 2. January 2006 erscheinen.", raw, loc, monday.LocaleDeDE)
        if err != nil {
        return t
    func main() {
        t := findReleaseDateString("Dieser Artikel wird am 9. März 2014 erscheinen.")


    2014-03-09 00:00:00 +0100 CET

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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