如何定义在Go中接受任意数量参数的函数类型？

Question

I try to write a function which takes any other function and wraps a new function around it. This is what I have tried so far:

package main

import (
    "fmt"
)

func protect (unprotected func (...interface{})) (func (...interface{})) {
    return func (args ...interface{}) {
        fmt.Println ("protected");
        unprotected (args...);
    };
}

func main () {
    a := func () {
        fmt.Println ("unprotected");
    };
    b := protect (a);
    b ();
}

When I compile this I get the error:

cannot use a (type func()) as type func(...interface { }) in function argument

Why is a function without arguments not compatible to a function with a variable number of arguments? What can I do to make them compatible?

Update: The protected function should be compatible with the original:

func take_func_int_int (f func (x int) (y int)) (int) {
    return f (1)
}

func main () {

    a := func (x int) (y int) {
        return 2 * x
    }
    b := protect (a)

    take_func_int_int (a)
    take_func_int_int (b)
}

Answer 1

Types are pretty concrete in Go. You could try

a := func(_ ...interface{}) {
    fmt.Println("unprotected")
}

func (...interface{}) does not mean "any function that takes any number of any kind of arguments", it means "only a function which takes a variable number of interface{} arguments"

Alternatively rather than func(...interface{}) you can just use interface{} and the reflect package. See http://github.com/hoisie/web.go for an example.

EDIT: Specifically, this:

package main

import (
    "fmt"
    "reflect"
)

func protect(oldfunc interface{}) (func (...interface{})) {
    if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
        panic("protected item is not a function")
    }
    return func (args ...interface{}) {
        fmt.Println("Protected")
        vargs := make([]reflect.Value, len(args))
        for n, v := range args {
            vargs[n] = reflect.ValueOf(v)
        }
        reflect.ValueOf(oldfunc).Call(vargs)
    }
}

func main() {
    a := func() {
        fmt.Println("unprotected")
    }
    b := func(s string) {
        fmt.Println(s)
    }
    c := protect(a)
    d := protect(b)
    c()
    d("hello")
}

Ouput is

Protected
unprotected
Protected
hello

EDIT: To answer the update

Like I said above, types are pretty concrete in Go. The protect function returns a type func(...interface{}) which will never be assignable to func(int)int. I think you're probably either over-engineering your problem or misunderstanding it. However, here's a highly discouraged code snippet that would make it work.

First change protect to also return values:

func protect(oldfunc interface{}) (func (...interface{}) []interface{}) {
    if reflect.TypeOf(oldfunc).Kind() != reflect.Func {
        panic("protected item is not a function")
    }
    return func (args ...interface{}) []interface{} {
        fmt.Println("Protected")
        vargs := make([]reflect.Value, len(args))
        for n, v := range args {
            vargs[n] = reflect.ValueOf(v)
        }
        ret_vals := reflect.ValueOf(oldfunc).Call(vargs)
        to_return := make([]interface{}, len(ret_vals))
        for n, v := range ret_vals {
                to_return[n] = v.Interface()
        }
        return to_return
    }
}

Then make a convert function:

func convert(f func(...interface{}) (func(int) int) {
    return func(x int) int {
        r := f(x)
        return r[0].(int)
    }
}

Then your call would look like

take_func_int_int(convert(b))

But I promise this isn't what you actually want to do.

Step back and try to rework the problem. I've completely killed type-safety in these examples. What are you trying to accomplish?