dongsheng4679 2014-02-12 11:05
浏览 83
已采纳

Go语言字符串常量

Is there a difference between an inline string and a constant string being used in Go, or is this being optimized entirely by the compiler?

Example benchmark code with 100B iterations:

package main

import "fmt"
import "time"
import "log"

func main() {
    // String
    start := time.Now()
    for i := 0; i < 100000000; i++ {
        x := "My String"
        if i % 1000000 == 0{
            fmt.Printf(x)
        }
    }
    elapsed := time.Since(start)
    log.Printf("
Took %s", elapsed)

    // Constant
    start2 := time.Now()
    const MY_STRING = "My String 2"
    for i := 0; i < 100000000; i++ {
        x := MY_STRING
        if i % 1000000 == 0 {
            fmt.Printf(x)
        }
    }

    elapsed2 := time.Since(start2)
    log.Printf("
Took %s", elapsed2)

    // Proof that the timer does work :)
    start3 := time.Now()
    time.Sleep(100 * time.Millisecond)
    elapsed3 := time.Since(start3)
    log.Printf("
Took %s", elapsed3)

}

Output:

My StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy StringMy String2009/11/10 23:00:00 
Took 0
My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 2My String 22009/11/10 23:00:00 
Took 0
2009/11/10 23:00:00 
Took 100ms

Program exited.
  • 写回答

3条回答 默认 最新

  • du1108 2014-02-12 12:06
    关注

    There is no difference in the compiled code between the two, so it should not affect your results. Take the following example file:

    package foo
    
    func foo() string {
        x := "Foo"
        return x
    }
    
    const MY_STRING = "Bar"
    
    func bar() string {
        x := MY_STRING
        return x
    }
    

    The assembler output shows that the two functions are the same (modulo the different string constants):

    $ go tool 6g -S foo.go
    
    --- prog list "foo" ---
    0000 (foo.go:3) TEXT    foo+0(SB),$0-16
    0001 (foo.go:3) FUNCDATA $0,gcargs·0+0(SB)
    0002 (foo.go:3) FUNCDATA $1,gclocals·0+0(SB)
    0003 (foo.go:3) TYPE    ~anon0+0(FP){string},$16
    0004 (foo.go:4) LEAQ    go.string."Foo"+0(SB),BX
    0005 (foo.go:4) MOVQ    (BX),CX
    0006 (foo.go:4) MOVQ    8(BX),BP
    0007 (foo.go:5) MOVQ    CX,~anon0+0(FP)
    0008 (foo.go:5) MOVQ    BP,~anon0+8(FP)
    0009 (foo.go:5) RET     ,
    
    --- prog list "bar" ---
    0010 (foo.go:10) TEXT    bar+0(SB),$0-16
    0011 (foo.go:10) FUNCDATA $0,gcargs·1+0(SB)
    0012 (foo.go:10) FUNCDATA $1,gclocals·1+0(SB)
    0013 (foo.go:10) TYPE    ~anon0+0(FP){string},$16
    0014 (foo.go:11) LEAQ    go.string."Bar"+0(SB),BX
    0015 (foo.go:11) MOVQ    (BX),CX
    0016 (foo.go:11) MOVQ    8(BX),BP
    0017 (foo.go:12) MOVQ    CX,~anon0+0(FP)
    0018 (foo.go:12) MOVQ    BP,~anon0+8(FP)
    0019 (foo.go:12) RET     ,
    

    As you can see, the string constant is loaded the same way in both cases.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥35 平滑拟合曲线该如何生成
  • ¥100 c语言,请帮蒟蒻写一个题的范例作参考
  • ¥15 名为“Product”的列已属于此 DataTable
  • ¥15 安卓adb backup备份应用数据失败
  • ¥15 eclipse运行项目时遇到的问题
  • ¥15 关于#c##的问题:最近需要用CAT工具Trados进行一些开发
  • ¥15 南大pa1 小游戏没有界面,并且报了如下错误,尝试过换显卡驱动,但是好像不行
  • ¥15 没有证书,nginx怎么反向代理到只能接受https的公网网站
  • ¥50 成都蓉城足球俱乐部小程序抢票
  • ¥15 yolov7训练自己的数据集