dongmei8209
2016-11-18 05:53
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已采纳

如何在GoLang程序中运行二进制文件？

I want to execute Binary Files inside GoLang Program.

Here is my code:

package main

import (
    "fmt"
    "os/exec"
)

func main() {
    output, _ := exec.Command("/home/user/Golang/bin/hello").Output()
    fmt.Println(output)
}

But I get the output as: []

Thanks in advance.

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我想在GoLang程序中执行二进制文件。

这是我的 代码： 

 包main 
 
import（
“ fmt” 
“ os / exec” 
）
 
func main（）{
输出，  _：= exec.Command（“ / home / user / Golang / bin / hello”）。Output（）
 fmt.Println（output）
} 
   
 
 <  p>但是我得到的输出为：[]  
 
 
谢谢。
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2条回答 默认 最新

  • douzhuo6931 2017-04-11 03:42
    已采纳

    When I'm looking at the source of the exec.Command() it doesnt return an error but only returns Cmd which is struct in the package exe : source

    ....

func Command(name string, arg ...string) *Cmd {
    cmd := &Cmd{
        Path: name,
        Args: append([]string{name}, arg...),
    }
    if filepath.Base(name) == name {
        if lp, err := LookPath(name); err != nil {
            cmd.lookPathErr = err
        } else {
            cmd.Path = lp
        }
    }
    return cmd
}

....

    I have succesfully got the binary file running using this code : 

    package main

import (

    "fmt"
    "os/exec"
)

func main() {
    command:= exec.Command("Your binary file path")

    // set var to get the output
    var out bytes.Buffer

     // set the output to our variable
     command.Stdout = &out
     err = command.Run()
     if err != nil {
         log.Println(err)
     }

    fmt.Println(out.String())
}

    This one works for me for running a binary file that will print some random string.

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  • dongqiu3709 2016-11-18 06:25

    I can get the output.

    package main

import (
    "fmt"
    "os/exec"
)

func main() {
    output, err := exec.Command("/Users/duguying/gopath/bin/test").Output()
    if err!=nil {
        fmt.Println(err.Error())
    }
    fmt.Println(string(output))
}

    check you binary file first or binary filepath is correcting. try to print out your error message.

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