doujie9882 2016-01-10 11:28
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故意int溢出

I'm using the hash function murmur2 which returns me an uint64.

I want then to store it in PostgreSQL, which only support BIGINT (signed 64 bits).

As I'm not interested in the number itself, but just the binary value (as I use it as an id for detecting uniqueness (my set of values being of ~1000 values, a 64bit hash is enough for me) I would like to convert it into int64 by "just" changing the type.

How does one do that in a way that pleases the compiler?

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  • dqqpf32897 2016-01-10 11:36
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    You can simply use a type conversion:

    i := uint64(0xffffffffffffffff)
    i2 := int64(i)
    fmt.Println(i, i2)
    

    Output:

    18446744073709551615 -1
    

    Converting uint64 to int64 always succeeds: it doesn't change the memory representation just the type. What may confuse you is if you try to convert an untyped integer constant value to int64:

    i3 := int64(0xffffffffffffffff) // Compile time error!
    

    This is a compile time error as the constant value 0xffffffffffffffff (which is represented with arbitrary precision) does not fit into int64 because the max value that fits into int64 is 0x7fffffffffffffff:

    constant 18446744073709551615 overflows int64
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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