使用AWS SAM 3秒后AWS Lambda函数超时-GoLang

Question

I am new to AWS and GoLang and I am trying to execute my Lambda function via AWS SAM cli. But everytime I try to do so I get the following error:

I0517 07:51:11.052078      13 main.go:62] Thumbnail Lambda successfully started 
I0517 07:51:13.696304      13 utils.go:99] Needed directories successfully created
2019-05-17 09:51:14 Function 'Thumbnail' timed out after 3 seconds
2019-05-17 09:51:14 Function returned an invalid response (must include one of: body, headers or statusCode in the response object). Response received:

I did not want to copy information I pass in the HTTP request since its sensitive.

Any idea how I can modify this 3 second timeout?

Answer 1

I am using template.yml in order to set up my lambda. I forgot to re-build and re-run sam local start-api when I introduced Timeout property to it. Honest mistake, thank you for your time.

Answer 2

The default timeout of Lambda functions is 3 seconds. You can set any value by updating the Timeout property in your SAM template, e.g.

ExampleLambda:
  Type: AWS::Serverless::Function
  Properties:
    CodeUri: .
    Handler: index.handler
    Runtime: nodejs10.x
    Timeout: 10