将字符串类型转换为int

Question

Ok, so I've been having difficulties with the type conversion of a string to byte write. This is the compiler error:

cannot use row[5] (type uint8) as type string in function argument

cannot use &v (type *Field) as type int in function argument

This is an example of row[5]: $15,000.00

Ive declared a struct:

type Field struct {
Eia uint8
}

here is the main implementation:

for {
    record, err := reader.Read()
    if err == io.EOF {
        break
    } else if err != nil {
        panic(err)
    }

    var v Field
    for _, row := range record {
        eia, err := strconv.ParseInt(row[5], 8, &v) // Estimated Incoming Amount
        if err == nil {
            fmt.Printf("%+v
", v)
        } else {
            fmt.Println(err)
            fmt.Printf("%+v
", v)
        }

Can anyone please explain to me how strconv can convert the row to a integer?

Answer 1

If you made a complete example on http://play.golang.org/ it'd be easier to give you a complete solution.

ParseInt() takes the string (you might have to do string(row[5])), the base (you probably meant 10) and the bitsize (that's where you should put 8).

It retuns an int (eia), it doesn't put it into the struct as it looks like you are trying.

Instead do if err == nil { v.Eia = eia }.