doudeng2057
doudeng2057
2019-05-06 16:01
浏览 256
已采纳

正则表达式,用于匹配标签的最后一次出现

I am trying to extract the contact link from the HTML code below. I have tried this but doesn't seem to work:

\"([^\"]*)\"(.*?)?\>(Kontakt)

and some part HTML-code:

<li id="cc-nav-view-2315645627" class="jmd-nav__list-item-0">
    <a href="/" data-link-title="Start" class="cc-nav-current j-nav-current jmd-nav__link--current">Start</a>
</li>
<li id="cc-nav-view-2315645625" class="jmd-nav__list-item-0">
    <a href="/öffnungszeiten-schließzeiten/" data-link-title="Öffnungszeiten &amp; Schließzeiten">Öffnungszeiten &amp; Schließzeiten</a>
</li>
<li id="cc-nav-view-2316315025" class="jmd-nav__list-item-0">
   <a href="/flyer/" data-link-title="Flyer">Flyer</a>
</li>
<li id="cc-nav-view-2315732425" class="jmd-nav__list-item-0">
    <a href="/anfahrt/" data-link-title="Anfahrt">Anfahrt</a></li>
<li id="cc-nav-view-2315645825" class="jmd-nav__list-item-0">
    <a href="/kontakt-termin-verbeinaren/" data-link-title="Kontakt / Termin verbeinaren">Kontakt / Termin verbeinaren</a>
</li>

I need to get the last a href occurrence with the contact link, but regexp returns the full string.

Check this link.

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1条回答 默认 最新

  • duanjiu1950
    duanjiu1950 2019-05-06 18:37
    已采纳

    This expression might help you to design a desired one to do so:

    (.*)(<a href=")([A-z0-9-\/]+)(".*)
    

    It swipe from beginning using (.*) to the last href, then you can add any boundary that you wish to capture that target URL.

    enter image description here

    Graph

    This graph shows how it works:

    enter image description here

    I'm not so sure, if you want just the URL or the entire tag. If you wish to get the entire tag, then the expression can be simply modified to something similar to:

    (.*)((<a href=")(.*)(\<\/a\>))
    
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