doudao2407
doudao2407
2015-01-04 07:43
浏览 199
已采纳

默认情况下,Go程序中启动了多少个goroutine?

package main

import (
    //"time"
    "runtime"
    "fmt"
)

func main() {
    //time.Sleep(100 * time.Millisecond)//By adding this number of goroutine increases
fmt.Println(runtime.NumGoroutine())
}

I am trying to find out the number of goroutines in a program. My code is here. While coding this I noticed default number of goroutines is 4.

For me:

  • main is one goroutine
  • garbage collector is one goroutine

What are the others?

By adding the time.Sleep (above), the number of goroutines increases to 5. What is the reason for this?

  • 点赞
  • 写回答
  • 关注问题
  • 收藏
  • 邀请回答

1条回答 默认 最新

  • duanpi2033
    duanpi2033 2015-01-04 09:23
    已采纳

    Actually, memory management takes more than one goroutine ...

    The 4 initial goroutines are:

    • the main goroutine
    • the background sweeper (the phase of the garbage collection which is concurrent)
    • the scavenger (also part of the garbage collector)
    • the finalizer goroutine (exclusively running the finalizers eventually attached to objects)

    Then, the time.Sleep function is called. It requires a timer. Timers are implemented in the runtime, through an additional goroutine (timerproc), which processes events stored in the timer heap. This goroutine is lazily started when the first timer is added to the heap.

    Hence, you finally get 5 goroutines.

    点赞 评论

相关推荐