I'm a beginner of golang and I'm learning the goroutine and channel. Intuitively, I consider a gorountine in golang is essentially a thread running independently. Therefore, if there are more than one goroutine, the execution order won't be guaranteed. Hence, the following code should output "ping" and "pong" in a random order. However, what I observed is that the program yields "ping" and "pong" in turn. Can anyone explain the reason for me? Any reply would be helpful. Thanks!
Another intriguing observation I found is that if I don't call sleep function inside the printer function, the program will output in a random order.
package main
import (
"fmt"
"time"
)
func pinger(c chan string) {
for i := 0; ; i++ {
c <- "ping"
}
}
func printer(c chan string) {
for {
msg := <- c
fmt.Println(msg)
time.Sleep(time.Second * 1)
}
}
func ponger(c chan string) {
for i := 0; ; i++ {
c <- "pong"
}
}
func main() {
var c chan string = make(chan string)
go pinger(c)
go ponger(c)
go printer(c)
var input string
fmt.Scanln(&input)
}
