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drtppp75155 2014-07-21 21:29
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xml.NewDecoder(resp.Body)。给出EOF错误_GOLang的解码

I'm trying to Decode XML from body a html response.

=>I saved this response body as string to a Variable and successfully decoded Using xml.Unmarshal Function .Code for that :

    err = xml.Unmarshal([]byte(outs), &v)
       if err != nil {
    fmt.Printf("error is here: %v", err)
    return
                       }

So I think problem is NOT with actual Content of Response body.

Now My Actual Code :

req1, err := http.NewRequest("GET", concat([]string{domain, defects_link}), nil)
error_handler(err)
req1.Close = true //I tried with and without this line 

resp1, err := client.Do(req1)
error_handler(err)

fmt.Printf("
 %s 
", resp1.Status)

defer resp1.Body.Close()//I tried with and without this line
conts1, err := ioutil.ReadAll(resp1.Body)
error_handler(err)
fmt.Println("Response Body is Here :", string(conts1))//Contents are Printed Here

Response is printed in last line of above code.But below code is giving "Error :EOF"

    if err := xml.NewDecoder(resp1.Body).Decode(&v); err != nil {
    fmt.Printf("error is : %v", err)

    return
}

What is wrong in my code.Kindly Help

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1条回答 默认 最新

  • douxian1939 2014-07-21 22:11
    关注

    If you already read the Body io.ReadCloser once (with conts1, err := ioutil.ReadAll(resp1.Body)), you cannot ask another function to read it again (or you will get the EOF error message).

    I saved this response body as string to a Variable and successfully decoded Using xml.Unmarshal Function.

    That seems the easiest approach to use the body content multiple times.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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