在Go中，是否可以有一个指向带参数的成员函数/方法的指针？

Question

If I have

type Foo struct {
    // some data
}

func (f *Foo) Op1() bool {
    // perform operation and return a bool
}

func (f *Foo) Op2(other int) bool {
    // perform a different operation using internal data
    // and the passed in parameter(s)
}

I know I can store a pointer to the first method.

fn := f.Op1

and call it

if fn(f) { // do something }

But what if I want to do the same with Op2? I am currently faking it by defined a wrapper function which takes a Foo and the values and calls the operation. But that is a lot of boiler plate code.

Answer 1

Using method expressions

In this case, we get a reference from the type, then you need to pass an instance as the first argument.

fn2 := (*Foo).Op2
f := &Foo{}
fn2(f, 2)

Referencing an instance method

In this case, the instance is already bind to the method and you can just provide the arguments:

fn2 := f.Op2
fn2(2)

Playground: https://play.golang.org/p/e0gUIHzj7Z