在Go中初始化成员时是否只能使用返回值之一？

Question

I understand how to use multiple return values in go. I further understand that in most cases one of the returns is an error, so ignoring returned values can be dangerous.

Is there a way to ignore a value in struct initializer like this? The below example does not work as Split returns two values, but I am interested only in the first one. I can of course create a variable but...

someFile := "test/filename.ext"

contrivedStruct := []struct{
    parentDir string
}{
    { parentDir: filepath.Split(someFile) },
}

Answer 1

It's not possible to use only one of the return values when initializing members in Go.

Using variables clearly expresses your intent.

Go sometimes feels like it could be more succinct, but the Go authors favoured readability over brevity.

Alternatively, use a wrapper function. There are several 'Must' wrapper functions in the standard library, like: template.Must.

func first(args ...string) string {
    return args[0]
}

For your particular example, splitting paths, see filepath.Base or filepath.Dir.