Your Int type is not an alias of int, it's a new type with int being its underlying type. This type of conversion is not supported / allowed by the language spec. More specifically, converting a slice type to another where the element type is different is not allowed.
The safe way
If you only need an []int "view" of the []Int, the safe way to "convert" would be to create a copy of the []Int slice but with a type of []int, and use a for range loop and convert each individual element from Int to int type:
var c = []Int{1, 2}
x := make([]int, len(c))
for i, v := range c {
x[i] = int(v)
}
fmt.Println(x)
Output (try it on the Go Playground):
[1 2]
The unsafe way
There is also an "unsafe" way:
var c = []Int{1, 2}
var x []int = *(*[]int)(unsafe.Pointer(&c))
fmt.Println(x)
Output is the same. Try this one on the Go Playground.
What happens here is that the address of c (which is &c) is converted to unsafe.Pointer (all pointers can be converted to this), which then is converted to *[]int (unsafe.Pointer can be converted to any pointer type), and then this pointer is dereferenced which gives a value of type []int. In this case it is safe because the memory layout of []Int and []int is identical (because Int has int as its underlying type), but in general, use of package unsafe should be avoided whenever possible.
If Int would be a "true" alias
Note that if Int would be a "true" alias to int, the conversion would not even be needed:
var c = []Int{1, 2}
var x []int = c
fmt.Println(x)
Output is the same as above (try it on the Go Playground). The reason why this works is because writing []Int is identical to writing []int, they are the same type, so you don't even need a conversion here.
By using a slice type
Also note that if you would create a new type with []int as its underlying type, you could use type conversion:
type IntSlice = []int
func main() {
var c = IntSlice{1, 2}
var x []int = []int(c)
fmt.Println(x)
}
Output is again the same. Try this one on the Go Playground.