了解Go中的time.Parse函数

Question

I am currently porting code from go to c# and came across this (simplified) piece of code. I do know that it converts a given string 171228175744.085 using a given format 060102150405.

The official docs only have examples using common formats like 2017-Feb-1, not this format (a possible timestamp?)

I do know that this will result in the time beeing 2017-12-28 17:57:44.085 +0000 UTC, but I do not have a clue how, because I have no information what the string 171228175744.085 and layout represent. I do know that some of this information is GPS related. So, my question is: Does anyone know how to do this in c#?

package main

import (
    "fmt"
    "time"
)

func main() {
    t, err := time.Parse("060102150405", "171228175744.085")
    if err == nil{
        fmt.Println(t)
    }

}

Answer 1

The docs around time.Format explain what the format means.

Quoting:

Format returns a textual representation of the time value formatted
according to layout, which defines the format by showing how the 
reference time, defined to be

Mon Jan 2 15:04:05 -0700 MST 2006

The format string in your example: 060102150405 tells the time parser to look for the following:

• 06: year
• 01: month
• 02: day of the month
• 15: hour of the day
• 04: minute
• 05: second

This is a convenient way of telling the parser how it should interpret each number. If you look carefully, you'll see that numbers are not reused so when you say 06, the parser matches it to 2006.

In C#, you can use datetime.ParseExact. Something along the lines of:

DateTime.ParseExact(dateString, "yyMMddhhmmss", some_provider);

(note: I have not tried the C# snippet above. You may need to adjust it)