drouie2014 2018-05-10 20:15
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在这两个迭代器中减少重复的好方法是什么?

I wrote an iterator for easier access to some paged DB results but what's a good way to reduce the duplication?

foo_iterator.go

type FooIterator struct {
    hasNext   bool
    app       *App
    batchSize int
}

func NewFooIterator(app *App, batchSize int) *FooIterator {
    return &FooIterator{
        hasNext:   true,
        app:       app,
        batchSize: batchSize,
    }
}

func (it *FooIterator) HasNext() bool {
    return it.hasNext
}

func (it *FooIterator) Next() []*model.Foo {
    offset := 0
    batch := it.app.GetAllFoosInPages(offset, it.batchSize)
    if len(batch) < it.batchSize {
        it.hasNext = false
    }
    offset += it.batchSize
    return batch
}

bar_iterator.go

type BarIterator struct {
    hasNext   bool
    app       *App
    batchSize int
}

func NewBarIterator(app *App, batchSize int) *BarIterator {
    return &BarIterator{
        hasNext:   true,
        app:       app,
        batchSize: batchSize,
    }
}

func (it *BarIterator) HasNext() bool {
    return it.hasNext
}

func (it *BarIterator) Next() []*model.Bar {
    offset := 0
    batch := it.app.GetAllBarsInPages(offset, it.batchSize)
    if len(batch) < bi.batchSize {
        it.hasNext = false
    }
    offset += it.batchSize
    return batch
}

Usage

fooIterator := NewFooIterator(a, 100)

for fooIterator.HasNext() {
    fooBatch := rolesIterator.Next()
    // Do stuff
}

They're both so similar there must be some good way to share code but everything I have tried seems awkward.

  • 写回答

1条回答 默认 最新

  • douzhun5971 2018-05-10 20:29
    关注

    Write a common iterator that calls a function to get more data:

    type Iterator struct {
        more      func(offset int, batchSize int) (int, interface{})
        hasNext   bool
        batchSize int
        offset    int
    }
    
    func (it *Iterator) HasNext() bool {
        return it.hasNext
    }
    
    func (it *Iterator) Next() interface{} {
        n, batch := it.more(it.offset, it.batchSize)
        if n < it.batchSize {
            it.hasNext = false
        }
        it.offset += n
        return batch
    }
    

    Use it like this:

    func NewFooIterator(app *App, batchSize int) *Iterator {
        return &Iterator{
            hasNext:   true,
            batchSize: batchSize,
            more: func(offset int, batchSize int) (int, interface{}) {
                batch := it.app.GetAllFoosInPages(offset, it.batchSize)
                return len(batch), batch
            },
        }
    }
    
    fooIterator := NewFooIterator(a, 100)
    
    for fooIterator.HasNext() {
        fooBatch := fooIterator.Next().([]*model.Foo)
        // Do stuff
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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