dongqi19827 2013-07-03 14:00
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GoLang:无法在多个分配中将[] byte分配给z(类型字符串)

I'm trying to find the contents of files within a folder, so I'm listing what's in the folder then while looping through it I'm trying to read the files.

files, _ := ioutil.ReadDir("documents/")
for _, f := range files {
        //fmt.Println(f.Name())

    z := "documents/" + f.Name()
    fmt.Println(z) // prints out 'documents/*doc name*' recursively
    z, err := ioutil.ReadFile(z) // This line throws up the error

The error I get is: test.go:85: cannot assign []byte to z (type string) in multiple assignment

Any help? (This is my first time coding in Go)

Thanks!

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1条回答 默认 最新

  • douyi6922 2013-07-03 14:04
    关注

    You can convert []byte to string, but you cannot convert one value of a multiple return valued function.

    buf, err := ioutil.ReadFile(z)
    if err != nil {
            log.Fatal(err)
    }
    z = string(buf)
    

    However, quite often it's better to not convert binary data to strings and work directly with buf.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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