SO, I need your help. I couldn’t find anything on that topic. Golang is a freshly baked language so it’s quite hard to find answers quick for a newcomers like me.
1条回答 默认 最新
- doufei8250 2011-08-05 22:55关注
The predeclared Go
int
type size is implementation-specific, either 32 or 64 bits (Numeric types).Here's an example of converting big-endian
int
s tobyte
s (uint8
s).package main import ( "encoding/binary" "fmt" "reflect" ) func IntsToBytesBE(i []int) []byte { intSize := int(reflect.TypeOf(i).Elem().Size()) b := make([]byte, intSize*len(i)) for n, s := range i { switch intSize { case 64 / 8: binary.BigEndian.PutUint64(b[intSize*n:], uint64(s)) case 32 / 8: binary.BigEndian.PutUint32(b[intSize*n:], uint32(s)) default: panic("unreachable") } } return b } func main() { i := []int{0, 1, 2, 3} fmt.Println("int size:", int(reflect.TypeOf(i[0]).Size()), "bytes") fmt.Println("ints:", i) fmt.Println("bytes:", IntsToBytesBE(i)) }
Output:
int size: 4 bytes ints: [0 1 2 3] bytes: [0 0 0 0 0 0 0 1 0 0 0 2 0 0 0 3]
or
int size: 8 bytes ints: [0 1 2 3] bytes: [0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 2 0 0 0 0 0 0 0 3]
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