dow98764 2015-02-19 10:58
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如何使用fmt.Sscan将整数解析为数组?

I'm trying to scan a list of integers from a string into an array (or alternatively, a slice)

package main

import "fmt"

func main() {
    var nums [5]int
    n, _ := fmt.Sscan("1 2 3 4 5", &nums)  // doesn't work
    fmt.Println(nums)
}

What do I need to pass as second argument to Sscan in order for this to work?

I know I could pass nums[0], nums[1] ... etc., but I'd prefer a single argument.

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3条回答 默认 最新

  • dongwuchu0314 2015-02-19 12:00
    关注

    I don't think this is possible as a convenient one-liner. As Sscan takes ...interface{}, you would need to pass slice of interfaces as well, hence converting your array first:

    func main() {
        var nums [5]int
    
        // Convert to interfaces
        xnums := make([]interface{}, len(nums))
        for n := range nums {
            xnums[n] = &nums[n]
        }
    
        n, err := fmt.Sscan("1 2 3 4 5", xnums...)
        if err != nil {
            fmt.Printf("field %d: %s
    ", n+1, err)
        }
    
        fmt.Println(nums)
    }
    

    http://play.golang.org/p/1X28J7JJwl

    Obviously you could mix different types in your interface array, so it would make the scanning of more complex string easier. For simply space-limited integers, you might be better using strings.Split or bufio.Scanner along with strconv.Atoi.

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