使用星号（*）在Go中指定宽度和精度

Question

The official fmt pacakge documentation at golang.org says this in respect to specifying width and precision -

Either or both of the flags may be replaced with the character '*', causing their values to be obtained from the next operand, which must be of type int.

How will the asterisk (*) be used, say, for example, in the following scenario -

 var f float32 = 12.3456789
 fmt.Printf("%6.3f", f)

Answer 1

It would be

var f float32 = 12.3456789
fmt.Printf("%*.*f", 20, 1, f)

See more at:

• https://github.com/golang/go/blob/8f4f1f63e9d5d171a669d0a9c4594bbaaf9ea6f7/src/fmt/fmt_test.go#L1590