在golang中无需结构即可对JSON数据进行最少的修改

Question

I have a solr response in JSON format which looks like this:

 {
  "responseHeader": {
    "status": 0,
    "QTime": 0,
    "params": {
      "q": "solo",
      "wt": "json"
    }
  },
  "response": {
    "numFound": 2,
    "start": 0,
    "docs": [
      {
          <Large nested JSON element>
      },
      {
          <Large nested JSON element>
      }
    ]
  }
}

Now, in my Golang app, I would like to quickly remove the "responseHeader" so that I can return the "response" alone. How can I do this without creating large structures?

---

Edit 1

The answer by evanmcdonnal was the solution to this problem, but it had some minor typos, this is what I ended up using:

var temp map[string]interface{}

if err := json.Unmarshal(body, &temp); err != nil {
    panic(err.Error())
}

result, err := json.Marshal(temp["response"])

Answer 1

Here's a really brief example of how to do this quickly and easily. The steps are; unmarshal into the universal map[string]interface{} then, assuming no errors, marshal only the inner object which you want.

var temp := &map[string]interface{}

if err := json.Unmarshal(input, temp); err != nil {
     return err;
}

return json.Marshal(temp["response"])