I am trying to scrape product video links (which are generated dynamically by another web service. The location is under the product images on the left side). You can check following link, https://www.tokopedia.com/chocoapple/ready-stock-bnib-iphone-128gb-7-plus-jet-black-garansi-apple-1-tahun-10?src=topads The google chrome "inspect element" shows the div tag. But The same tag is not present in the page source. How to do it? I am looking into goQuery to implement the task but not sure will it work or not. I am not a web developer so please consider giving suggestions if my question description is not specific. Thank you.
3条回答 默认 最新
- doushi4633 2017-08-27 14:36关注
If the tag is not in the source, then GoQuery will not work. GoQuery is for parsing HTML source using a jQuery-like API.
You need to first process the webpage with a headless WebKit like phantomjs, chromeless, or puppeteer. Each of these tools will allow you to process all the Javascript on the webpage before processing it. This way, the AJAX for rendering the video you are interest in will be processed and the source will be updated. You can then download the corresponding source which should have the div in it.
本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
悬赏问题
- ¥15 CCF-CSP 2023 第三题 解压缩(50%)
- ¥30 comfyui openpose报错
- ¥20 Wpf Datarid单元格闪烁效果的实现
- ¥15 图像分割、图像边缘提取
- ¥15 sqlserver执行存储过程报错
- ¥100 nuxt、uniapp、ruoyi-vue 相关发布问题
- ¥15 浮窗和全屏应用同时存在,全屏应用输入法无法弹出
- ¥100 matlab2009 32位一直初始化
- ¥15 Expected type 'str | PathLike[str]…… bytes' instead
- ¥15 三极管电路求解,已知电阻电压和三级关放大倍数