dousi9215 2018-05-28 14:20
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将字节数组转换为字符串数组[重复]

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In the following method, I attempted to redefine the string method on the IPAddr type by appending bytes to an array of string

type IPAddr [4]byte

func (ip IPAddr) String() string {
    var s []string
    for _, i := range ip {
        s = append(s, i)
    }
    return fmt.Sprintf(strings.Join(s, "."))
}

cannot use i (type byte) as type string in append

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  • douwei1904 2018-05-28 14:22
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    Since your type is an array with a small length, so I would recommend just building the string without ranging over the elements:

    func (ip IPAddr) String() string {
        return fmt.Sprintf("%d.%d.%d.%d", ip[0], ip[1], ip[2], ip[3])
    }
    

    https://play.golang.org/p/nOSj-EyXuyf

    If you want to implement your solution by joining the string slice, you need to convert the bytes to their decimal representation using the strconv package:

    func (ip IPAddr) String() string {
        s := make([]string, 0, len(ip))
        for _, i := range ip {
            s = append(s, strconv.Itoa(int(i)))
        }
        return fmt.Sprintf(strings.Join(s, "."))
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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