dsz1966 2017-04-03 04:14
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如何使用毒蛇将环境变量解组到切片?

I have the following code:

package main

import (
    "log"

    "github.com/spf13/viper"
)

func main() {
    viper.SetEnvPrefix("myprefix")
    viper.SetDefault("languages", []string{"french", "spanish"})
    viper.BindEnv("name")
    viper.BindEnv("languages")

    type config struct {
        Name      string
        Languages []string
    }

    var C config

    err := viper.Unmarshal(&C)
    if err != nil {
        log.Fatalln("unable to decode into struct, %v", err)
    }

    log.Println(C)
    log.Println(len(C.Languages))
}

When $MYPREFIX_LANGUAGES is not set the length of C.Languages is 2 (eg the default). When I set $MYPREFIX_LANGUAGES to "english spanish french russian" I get a length of 1. It is just taking the variable as 1 long string, not a slice. How do I get a slice ([]string{"english", "spanish", "french", "russian"}?

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1条回答 默认 最新

  • dongren9739 2017-04-05 21:21
    关注

    Thanks to @Charlino here is the answer:

    package main
    
    import (
        "log"
    
        "github.com/spf13/viper"
    )
    
    func main() {
        viper.SetEnvPrefix("myprefix")
        viper.SetTypeByDefaultValue(true)
        viper.SetDefault("languages", []string{"french", "spanish"})
        viper.BindEnv("name")
        viper.BindEnv("languages")
    
        type config struct {
            Name      string
            Languages []string
        }
    
        var C config
    
        err := viper.Unmarshal(&C)
        if err != nil {
            log.Fatalln("unable to decode into struct, %v", err)
        }
    
        log.Println(C)
        log.Println(len(C.Languages))
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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