dongren1977 2019-02-20 21:25
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在具有任意结尾的元素的GO xml中进行解析

I try to parse xml file that has elements with arbitrary endings

Example of xml with Array0 and Array1:

<GetPriceChangesForReseller>
          <PriceContractArray0 actualtype="PriceContract">
            <EndUserPrice>1990,00</EndUserPrice>     
          </PriceContractArray0>
          <PriceContractArray1 actualtype="PriceContract">        
            <EndUserPrice>2290,00</EndUserPrice>
          </PriceContractArray1>  
</GetPriceChangesForReseller>

How can I work with this case?

a part of my code:

package main

import (
    "encoding/xml"
    "fmt"
    "io/ioutil"
    "os"
)


type GetPriceChangesForReseller struct {
    XMLName                    xml.Name             `xml:"GetPriceChangesForReseller"`
    GetPriceChangesForReseller []PriceContractArray `xml:"PriceContractArray"`
}


type PriceContractArray struct {
    XMLName             xml.Name `xml:"PriceContractArray"`
    Price               string   `xml:"Price"`
func main() {

// Open our xmlFile
xmlFile, err := os.Open("GetPriceChangesForReseller.xml")
// if we os.Open returns an error then handle it
if err != nil {
    fmt.Println(err)
}

Thanks in advance!

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2条回答 默认 最新

  • dongxing1412 2019-02-20 22:08
    关注

    You can use the following structure (try it online!):

    type GetPriceChangesForReseller struct {
        XMLName xml.Name        `xml:"GetPriceChangesForReseller"`
        Items   []PriceContract `xml:",any"`
    }
    
    type PriceContract struct {
        Price string `xml:"EndUserPrice"`
    }
    

    It should work.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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