du548397507 2017-10-31 16:46
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大图书馆中的Lychrel数字

I'm trying to make a Lychrel number program in Go, but I'm running into some trouble. Using the "math/big" library, and with some extra print statements for debugging, my code looks like this:

func reverse(n *big.Int) *big.Int {
    var (
        m = n
        r = big.NewInt(0)
        z = big.NewInt(0)
        one = big.NewInt(1)
        ten = big.NewInt(10)
        )
    for {
        r.Mul(r, ten)
        d := z
        d.Mod(m, ten)
        r.Add(r, d)
        m.Div(m, ten)
        if m.Cmp(one) == -1 {
            return r
        }
    }
}

func radd(num *big.Int) *big.Int {
    newNum := num
    rnum := reverse(num)
    newNum = newNum.Add(num, rnum)
    fmt.Println(num, "+", rnum, "=", newNum)

    return newNum
}

func lychrel(arg int) bool {
    fmt.Println("Now testing", arg)
    num := big.NewInt(int64(arg))
    for i := 0; i < 50; i++ {
        num = radd(num)
        fmt.Println(i, ":", num)
        if num.Cmp(reverse(num)) == 0 {
            return false
        }
    }
    return true
}

While the analogous code without the big library works fine (save for eventual overflow errors), this version doesn't. When I do lychrel(196), for example, I get

Now testing 196
691 + 691 = 691
0 : 691
0 + 0 = 0
1 : 0

I can't figure out where it goes wrong. I hope I'm not missing something dumb, because I've spent all morning trying to get this to work.

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1条回答 默认 最新

  • duanmiexi2275 2017-10-31 17:10
    关注

    Package big

    import "math/big"
    

    func NewInt

    func NewInt(x int64) *Int
    

    NewInt allocates and returns a new Int set to x.

    func (*Int) Set

    func (z *Int) Set(x *Int) *Int
    

    Set sets z to x and returns z.

    You are assigning pointers, instead of values.

    m = n
    newNum := num
    

    Assign values,

    m = new(big.Int).Set(n)
    newNum := new(big.Int).Set(num)
    

    For example,

    package main
    
    import (
        "fmt"
        "math/big"
    )
    
    func reverse(n *big.Int) *big.Int {
        var (
            m   = new(big.Int).Set(n)
            r   = big.NewInt(0)
            z   = big.NewInt(0)
            one = big.NewInt(1)
            ten = big.NewInt(10)
        )
        for {
            r.Mul(r, ten)
            d := z
            d.Mod(m, ten)
            r.Add(r, d)
            m.Div(m, ten)
            if m.Cmp(one) == -1 {
                return r
            }
        }
    }
    
    func radd(num *big.Int) *big.Int {
        newNum := new(big.Int).Set(num)
        rnum := reverse(num)
        newNum = newNum.Add(num, rnum)
        fmt.Println(num, "+", rnum, "=", newNum)
        return newNum
    }
    
    func lychrel(arg int) bool {
        fmt.Println("Now testing", arg)
        num := big.NewInt(int64(arg))
        for i := 0; i < 50; i++ {
            num = radd(num)
            fmt.Println(i, ":", num)
            if num.Cmp(reverse(num)) == 0 {
                return false
            }
        }
        return true
    }
    
    func main() {
        lychrel(196)
    }
    

    Output:

    Now testing 196
    196 + 691 = 887
    0 : 887
    . . .
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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