Go中nil的类型

Question

How can I handle nil return type in switch-case operators?

func someFunc() interface{}{
    if 5>2{
        return nil
    }else if something{
        return 42
    }
    return nil
}

func main() {
    switch someFunc().(type) {
    case int:
    case types.Nil:
        fmt.Println("5>2")
    }
}

This code prints nothing, but I expected "5>2". How should I do it properly? https://play.golang.org/p/vAdiH925LDl

Answer 1

Use nil:

func main() {
    switch someFunc().(type) {
    case int:
    case nil:
        fmt.Println("5>2")
    }
}

https://play.golang.org/p/XcJwM2wnGZG