dsh1956 2018-04-13 02:56
浏览 428

Golang中的sync.Mutex和* sync.Mutex哪个更好?

In Golang, we can use:

type Data struct {
    lock  *sync.Mutex
}

or

type Data struct {
    lock  sync.Mutex
}

And, use like this:

func (d *Data) Update() {
   d.lock.Lock()
   defer d.lock.Unlock()
   // update
}

The difference I can think of is that *sync.Mutex needs instantiation to use only.

What is the difference between sync.Mutex and *sync.Mutex in Golang and which one is better?

  • 写回答

1条回答 默认 最新

  • duanhu7615 2018-04-13 05:27
    关注
    • I think you can regard *sync.Mutex as a simple pointer. If you want to use it, you should declare and init it, but if you use sync.Mutex, it has been inited.
    • BTW, in k8s source code, they always pass variable pointer to use, because passing struct will do a copy, but if you use pointer, all you need to pass is a pointer. ( I mean is you don't not need to have a copy spend).
    评论

报告相同问题?

悬赏问题

  • ¥15 如何用Labview在myRIO上做LCD显示?(语言-开发语言)
  • ¥15 Vue3地图和异步函数使用
  • ¥15 C++ yoloV5改写遇到的问题
  • ¥20 win11修改中文用户名路径
  • ¥15 win2012磁盘空间不足,c盘正常,d盘无法写入
  • ¥15 用土力学知识进行土坡稳定性分析与挡土墙设计
  • ¥70 PlayWright在Java上连接CDP关联本地Chrome启动失败,貌似是Windows端口转发问题
  • ¥15 帮我写一个c++工程
  • ¥30 Eclipse官网打不开,官网首页进不去,显示无法访问此页面,求解决方法
  • ¥15 关于smbclient 库的使用