dpqy77560 2016-11-14 11:38
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在Golang中使用EasyJSON

Let's say I have a struct like below:-

//easyjson:json
type JSONData struct {
    Data []string
}

I want to un-marshal the below json to JSONData struct

{"Data" : ["One", "Two", "Three"]} 

Can someone let me know how can I use easyjson to un-marshal a json in Golang? I could not find any example in their README

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  • dongshi6710 2016-11-14 12:01
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    I don't know why you trying to use easyjson. encoding/json is pretty fine to work with. But though here is the answer for you.

    NB: It would be better if you use encoding/json.

    //easyjson:json
    type JSONData struct {
        Data []string
    }
    

    After define this struct run easyjson <fileName-JSONData-is-defined>.go. this will create an extra go file containg

    func (v JSONData) MarshalJSON() ([]byte, error)
    func (v JSONData) MarshalEasyJSON(w *jwriter.Writer)
    func (v *JSONData) UnmarshalJSON(data []byte) errorfunc (v *JSONData) 
    func UnmarshalEasyJSON(l *jlexer.Lexer)
    

    those methods. Then (un-)marshal using

    d := &JSONData{}
    d.UnmarshalJSON([]byte(`{"Data" : ["One", "Two", "Three"]} `))
    // Or you could also use
    // json.Unmarshal(data, d) this will also call this d.UnmarshalJSON
    fmt.Println(d)
    

    A full example is here.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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