golang将func作为参数传递给另一个func

Question

Main question is "is it possible to pass any type func as param and how?". I am learning Go and want to make my own async wrap function like this:

func AsyncFunc(fn func(), args ...interface{}) chan bool {
    var done chan bool;

    go func() {
        fn(args...);
        done <- true;
    }();

    return done;
}

and call it:

max := func(a, b int) int {
    //some hard code what will be goroutine
    if a > b {return a};
    return b;
}

done := AsyncFunc(max, 5, 8);
//some pretty code
<- done;

P.S. sorry for my English if it is bad...

Edit1: I know it is useless, slow and danger. It is just my crazy idea what i want just realise.

Answer 1

i found the way to do what i want.

 package main


 import (
     "fmt"
 )


 func t1(t int) {
     fmt.Printf("%d
", t);
 }


 func t2(t string) {
     fmt.Printf("%s
", t);
 }


 func test(fn interface{}, data interface{}) {
     switch fn.(type) {
     case func(string):
         fn.(func(string))(data.(string))
     case func(int):
         fn.(func(int))(data.(int))
     }
 }


 func main() {
     test(t1, 123);
     test(t2, "test");
 }