duanhao5038 2019-02-26 23:27
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Golang正则表达式匹配并替换某个字符串后的第一个匹配项

Following up on my previous question about using Golang's regex to replace between strings. I now have a bit of complexity added to it. Here is what the contexts of my file looks like:

foo:
    blahblah
    MYSTRING=*
bar:
    blah
    blah
    MYSTRING=*

I need to replace what's between MYSTRING= and with a string of my choice (like previous stated in the original post). I can do that with:

var re = regexp.MustCompile(`(MYSTRING=).*`)
s := re.ReplaceAllString(content, `${1}stringofmychoice`)

But now I need to match and replace only after a certain occurrence. So that the contents of my file can look something like this:

foo:
    blahblah
    MYSTRING=foostring
bar:
    blah
    blah
    MYSTRING=barstring

ReplaceAllString obviously replaces everything, which is not what I want. Is there a way to only match and replace the first occurrence after a certain string?


For a bit of background about all of this. I'm trying to write a program to edit the contents of a given docker-compose.yml file and its environment variables. I need to edit the environment variable MYSTRING differently depending on what service it's listed under. In the example above, the two different services would be foo and bar.

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  • dta25920 2019-02-26 23:52
    关注

    You may use ReplaceAllStringFunc and use a regex like

    (?m)^bar:(?:
    \s{4}.*)+
    

    See the regex demo. It will match a bar block indented with four whitespaces. Then, after a match is obtained, you may use a regular ReplaceAllString on the match.

    See the Go demo:

    package main
    
    import (
        "fmt"
        "regexp"
    )
    
    const sample = `foo:
        blahblah
        MYSTRING=*
    bar:
        blah
        blah
        MYSTRING=*`
    
    func main() {
        re := regexp.MustCompile(`(?m)^bar:(?:
    \s{4}.*)+`)
        re_2 := regexp.MustCompile(`(MYSTRING=).*`)
        s := re.ReplaceAllStringFunc(sample, func(m string) string {
                    return re_2.ReplaceAllString(m, `${1}stringofmychoice`)
            })
        fmt.Println(s)
    }
    

    Here, the second occurrence is changed in the bar block:

    foo:
        blahblah
        MYSTRING=*
    bar:
        blah
        blah
        MYSTRING=stringofmychoice
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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