2016-12-10 20:42
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I am using golang regexp and I want to extract a pattern in a string.

For example, I can have the following name value pairs in the string:


I am looking for exactly the string "needle=haystack" and discard anything else.

It would be even better if I could just get the result to be exactly haystack.

How do I do this with regexp in golang?

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“ name1 = val1; name2 = val2; needle = haystack; name3 = val3”

我正在精确查找字符串“ needle = haystack”并丢弃其他任何内容。

如果我能得到准确的结果会更好 草垛。


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1条回答 默认 最新

  • douxing1353 2016-12-10 21:02

    I'm not entirely clear on what the goal is. If you're always looking for needle=haystack then you can use strings.Contains(str, "needle=haystack").

    If you really want to do it with regexes then it would be something like the code below.

    package main
    import (
    func main() {
        str := "name1=val1;name2=val2;needle=haystack;name3=val3"
        r := regexp.MustCompile("needle=([a-z]+);")
        found := r.FindString(str)
        if found == "" {
            fmt.Println("No match found")
        fmt.Println(found) // needle=haystack;
        submatches := r.FindStringSubmatch(str)
        fmt.Println(submatches) // [needle=haystack; haystack]
        if len(submatches) < 2 {
            fmt.Println("No submatch found")
        fmt.Println(submatches[1]) // haystack
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