在go中将3个字节转换为int？

Question

I know how to use "encoding/binary" to convert 4 bytes to an int, etc.

What is the most efficient way to convert just 3 bytes to an int?

Answer 1

Little endian:

n := int(uint(b[0]) | uint(b[1])<<8 | uint(b[2])<<16))

Big endian:

n := int(uint(b[2]) | uint(b[1])<<8 | uint(b[0])<<16))