Go语言中的静态类方法

Question

I am looking at the example code at: https://golang.org/pkg/net/rpc/

type Arith int

func (t *Arith) Multiply(args *Args, reply *int) error {
    *reply = args.A * args.B
    return nil
}

From an OOP perspective, Multiply seems like a static method which doesn't access any data in Arith class; as the variable t is not used. Does it mean that int in type Arith int does not have any significance?

Answer 1

This doesn't have anything to do with OOP, it's simply that the rpc package's convention works by exporting methods from an "object" (with object here meaning any value with a non-empty method set)

The int is significant as the type of Arith, but it's not significant in this particular example, since the receiver is never referenced in the methods.

So yes, this example is kind of like a static class, but try not to map Java OOP ideas to Go, because Go is very different, as there are no "classes" or inheritance.