dongpangfu6322 2018-10-06 09:14
浏览 31

查找[] byte切片中所有出现的字符串

I want to find the index of all occurrences of a string contained within a byte array.

func findAllOccurrences(data []byte, searches []string) map[string][]int {
    var results map[string][]int

    for _, search := range searches {
        firstMatch = bytes.Index(data, []byte(search))
        results[search] = append(results[search], firstMatch)

        // How do I find subsequent the rest of the matches?
    }

    return results
}

Finding the first Index() is simple enough, but how can I find all of them in an idiomatic way without consuming unnecessary memory?

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2条回答 默认 最新

  • douzhi9939 2018-10-06 18:34
    关注

    Okay, so here is the solution from my comment by reading the LastIndex instead of first, not sure if it is efficient, but this does work, you just get indexes in an inverted order, which you can always fix at the time of reading.

    package main
    
    import (
        "fmt"
        "bytes"
    )
    
    func main() {
        str1:= "foobarfoobarfoobarfoobarfoofoobar"
        arr := make([]string, 2)
        arr[0]="foo"
        arr[1]="bar"
        res:=findAllOccurrences([]byte(str1), arr)
        fmt.Println(res)
    }
    
    
    func findAllOccurrences(data []byte, searches []string) map[string][]int {
        results:= make(map[string][]int,0)
    
        for _, search := range searches {
        index := len(data)
        tmp:=data
        for true{
            match := bytes.LastIndex(tmp[0:index], []byte(search))
            if match==-1{
                break
            }else{
                index=match
                results[search]=append(results[search], match)
                }
            }
        }
    
        return results
    }
    

    Hope this helps! :)

    评论

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