用千位逗号golang格式化字符串格式

Question

I have this string "1,090"

I want to convert it to float

v := "1,090"
s, err := strconv.ParseFloat(v, 32)
if  err != nil {
    fmt.Printf("err: %s
", err)
    return
}
fmt.Printf("%T, %v
", s, s)

But it returns an error:

//err: strconv.ParseFloat: parsing "1,090": invalid syntax

So anybody know to convert it to float?

Answer 1

The reason it is failed because "1,090" has , comma in it. You have to remove the , from the string before you use strconv.ParseFloat(v, 32). One way to remove comma is by using strings.Replace():

v := "1,090"

v = strings.Replace(v, ",", "", -1)

s, err := strconv.ParseFloat(v, 32)
if  err != nil {
        fmt.Printf("err: %s
", err)
        return
}
fmt.Printf("%T, %v
", s, s)