du5910 2018-09-02 13:49
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Suppose I have a bitmap that I have set using the following commands

setbit key 0 1
setbit key 1 1
setbit key 2 0
setbit key 3 1
setbit key 4 1

When I run get on this key from the redis-cli I get the following result: "\xd8"

But when I do it using a go-redis API I get a different result which is this: � @

To get the above result I have used the following code:

package main

import (


func main() {
    client := redis.NewClient(&redis.Options{
        Addr:     "localhost:6379",
        Password: "",
        DB:       0,

    pong, _ := client.Ping().Result()

    client.SetBit("key", 0, 1)
    client.SetBit("key", 1, 1)
    client.SetBit("key", 2, 0)
    client.SetBit("key", 3, 1)
    client.SetBit("key", 4, 1)  

    res := client.Get("bmk").Val()


I cannot find it anywhere in the redis docs which kind of encoding the cli uses to produce such results. I would like to convert the results to the same format in my go program as well.

Can someone please tell me what kind of encoding this is and how can I convert the result received from the Redis API to the one obtained by the CLI ?

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  • donjd86266 2018-09-02 14:54

    The redis-cli and the Go program get the same result for GET on some key. The difference that you are observing is how the result value is formatted for output.

    The Go program in the question writes the data as is.

    The redis-cli code for encoding output is here. The function uses typical backslash escapes for newlines, quotes, etc and \x<hex number> for other non-printable bytes.

    Use the fmt package "%q" verb to output data in a similar format:

    ", res)

    If you need the exact same format, then a translation of the internal Redis function to Go required.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?



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