如何创建嵌入另一个结构的切片？

Question

I have the following:

https://play.golang.org/p/q2NUMzbw6-

package main

import "fmt"

type A struct {
    Name string
    Address string
}

type B struct {
    A
}

type C struct {
    A
}

type D struct {
    A
}

//....more structs that embed A

type myinterface interface {
    SetName(string)
    SetAddress(string)
}

func run() *A {
    // iterate over a slice of structs that embed A.... how????
    for _, s := range []*A{
        &B{}, &C{}, &D{},
    } {
        s.SetName("Bob")
        s.SetAddress("Maine")
        // do some other stuff that gets very verbose w/out a slice...
        return s.A
    }
}

func main() {
    a := run()
    fmt.Println(a)
}

I need to iterate through all of the structs that embed A but am having a hard time doing so. The above doesn't work "cannot use B literal (type *B) as type *A in array or slice literal". What is the best way?

Answer 1

Declare methods on A that satisfy the interface:

func (a *A) SetName(s string) {
    a.Name = s
}

func (a *A) SetAddress(s string) {
    a.Address = s
}

Use a slice of that interface in the range:

for _, s := range []myinterface{&B{}, &C{}, &D{}} {
   ...
}

playground example