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dst8922 2016-01-30 19:46
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无法使用golang解码XML,始终为空结构

I'm trying to decode XML with golang, but the following code gives an empty struct

Anyone can help?

When I run the following code, I always get

{{ packet} []}

Attached source code:

package main

import (
    "fmt"
    "encoding/xml"
//    "io/ioutil"
)

type Field struct {
    XMLName xml.Name `xml:"field"`
    name      string `xml:"name,attr"`
    shownameg string `xml:"showname,attr"`
    fields []Field
}

type Proto struct {
    XMLName xml.Name `xml:"proto"`
    name      string `xml:"name,attr"`
    shownameg string `xml:"showname,attr"`
    fields []Field
}

type Packet struct {
    XMLName xml.Name `xml:"packet"`
    protos []Proto   `xml:"proto"`
}

func main () {   
    data := []byte(`
<packet>
  <proto name="geninfo" pos="0" showname="General information" size="122">
    <field name="timestamp" pos="0" show="Jul 17, 2008 15:50:25.136434000 CST" showname="Captured Time" value="1216281025.136434000" size="122"/>
  </proto>
</packet>
    `)

    packet := Packet{}

    err := xml.Unmarshal([]byte(data), &packet)
    if err != nil {
        fmt.Println (err)
        return
    }

    fmt.Println (packet)

    for proto, _ := range (packet.protos) {
        fmt.Println (proto)
    }
}

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1条回答 默认 最新

  • dongyou2635 2016-01-30 19:49
    关注

    You need to export your struct fields as per https://golang.org/pkg/encoding/xml/#Unmarshal

    Because Unmarshal uses the reflect package, it can only assign to exported (upper case) fields. Unmarshal uses a case-sensitive comparison to match XML element names to tag values and struct field names.

    e.g.

    type Proto struct {
        XMLName xml.Name `xml:"field"`
        Name      string `xml:"name,attr"`
        Shownameg string `xml:"showname,attr"`
        Fields []Field
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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