dongxuandong2045
2019-02-21 14:21
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Golang:从一个字节解析位值

I need to parse a network packet which consists of two bytes: first one consists of 8 bits that set certain flags depending on their order (for instance) and the second one is uint8 (which is simple)

  • 1 - online
  • 0 - not active
  • 1 - isPretty
  • 1 - isHandsome
  • 0 - bald
  • 0 - deaf
  • 0 - mute
  • 0 - blind

How do I parse it from a byte primitive?

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我需要解析一个由两个字节组成的网络数据包:第一个由8位组成,这些数据位取决于 (例如),第二个是uint8(很简单)

  • 1-在线
  • 0-无效
  • 1-isPretty
  • 1-isHandsome
  • 0-秃头
  • 0-聋哑
  • 0-静音
  • 0-盲目

    如何从字节原语解析它?< / p>

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  • doupian9490 2019-02-21 14:34
    已采纳

    Some useful Go standard library packages for dealing with binary:

    For extracting single bits from a byte, you ought to use bitwise operators - |, & and >>.

    For example:

    package main
    
    import (
        "fmt"
    )
    
    func main() {
        v := byte(0xB2)
        if (v >> 4) & 1 == 1 {
            fmt.Println("bit 4 (counting from 0) is set")
        }
    }
    

    This checks bit 4 (with bit 0 being the lowest bit in the byte) by shifting the byte value 4 positions to the right and AND-ing with 1. You can check the other bits in your flag value similarly. Feel free to write a function that replaces the 4 in the sample above with an argument N to check bit number N.

    You can find more examples in other SO answers like this one or the ones @icza linked to in a comment.

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