关闭Go频道并同步go例程

Question

Im unable to terminate my WaitGroup in go and consequently can't exit the range loop. Can anybody tell me why. Or a better way of limiting the number of go routines while still being able to exit on chan close!

Most examples i have seen relate to a statically typed chan length, but this channel is dynamically resized as a result of other processes.

The print statement ("DONE!") in the example are printed showing that the testValProducer prints the right amount of times but the code never reaches ("--EXIT--") which means wg.Wait is still blocking somehow.

type TestValContainer chan string

func StartFunc(){
testValContainer            := make(TestValContainer)
go func(){testValContainer <- "string val 1"}()
go func(){testValContainer <- "string val 2"}()
go func(){testValContainer <- "string val 3"}()
go func(){testValContainer <- "string val 4"}()
go func(){testValContainer <- "string val 5"}()
go func(){testValContainer <- "string val 6"}()
go func(){testValContainer <- "string val 7"}()
wg  := sync.WaitGroup{}

// limit the number of worker goroutines
for i:=0; i < 3; i++ {
    wg.Add(1)
    go func(){
        v := i
        fmt.Printf("launching %v", i)
        for str := range testValContainer{
            testValProducer(str, &wg)
        }
        fmt.Println(v, "--EXIT --")  // never called
    }()
}

wg.Wait()
close(testValContainer)

}


func get(url string){
    http.Get(url)
    ch <- getUnvisited()
}


func testValProducer(testStr string, wg *sync.WaitGroup){
    doSomething(testStr)
    fmt.Println("done !") // called
    wg.Done() // NO EFFECT??
}

Answer 1

I might do something like this, it keeps everything easy to follow. I define a structure which implements a semaphore to control the number of active Go routines spinning up... and allows me to read from the channel as they come in.

package main

import (
    "fmt"
    "sync"
)

type TestValContainer struct {
    wg   sync.WaitGroup
    sema chan struct{}
    data chan int
}

func doSomething(number int) {
    fmt.Println(number)
}

func main() {
    //semaphore limit 10 routines at time
    tvc := TestValContainer{
        sema: make(chan struct{}, 10),
        data: make(chan int),
    }

    for i := 0; i <= 100; i++ {
        tvc.wg.Add(1)
        go func(i int) {
            tvc.sema <- struct{}{}
            defer func() {
                <-tvc.sema
                tvc.wg.Done()
            }()

            tvc.data <- i
        }(i)
    }
    // wait in the background so that waiting and closing the channel dont
    // block the for loop below
    go func() {
        tvc.wg.Wait()
        close(tvc.data)
    }()
    // get channel results
    for res := range tvc.data {
        doSomething(res)
    }

}