Golang：如何将image.image转换为uint16

Question

I am trying to use the go-skeltrack library with some depth images I have (Not using freenect). For that I need to modify the provided example by replacing the kinect images by my own. For that I have to read an image and convert it later to an []uint16 variable. The code which I tried is:

file, err := os.Open("./images/4.png")
if err != nil {
    fmt.Println("4.png file not found!")
    os.Exit(1)
}
defer file.Close()

fileInfo, _ := file.Stat()
var size int64 = fileInfo.Size()
bytes := make([]byte, size)

// read file into bytes 
buffer := bufio.NewReader(file)
_, err = buffer.Read(bytes)  

integerImage := binary.BigEndian.Uint16(bytes)

onDepthFrame(integerImage)

Where onDepthFrame is a function which has the form

func onDepthFrame(depth []uint16).

But I am getting the following error while compiling:

./skeltrackOfflineImage.go:155: cannot use integerImage (type uint16) as type []uint16 in argument to onDepthFrame

Which of course refers to the fact that I generated a single integer instead of an array. I am quite confused about the way that Go data types conversion works. Please help!

Thanks in advance for your help. Luis

Answer 1

binary.BigEndian.Uint16 converts two bytes (in a slice) to a 16-bit value using big endian byte order. If you want to convert bytes to a slice of uint16, you should use binary.Read:

// This reads 10 uint16s from file.
slice := make([]uint16, 10)
err := binary.Read(file, binary.BigEndian, slice)